SH Tele 500k pots & 470k resistor - doesn’t sound right

Revolutions

Finally got round to fitting 500k pots on my squier cv Tele after sticking a humbucker in it a while ago.

my plan was to use this wiring as I didn’t fancy the
middle position being bright.

I ran into a small problem in the lugs on the squier 3-way switch are different:

I tried both empty lugs for the 470k resistor & neither sounds great. Basically sounds like the bridge pickup without any bass.

Any suggestions as to what I might have missed? Oh, and yes it’s lefty so everything is flipped.

ICBM

If you didn’t want the middle position bright you’ve got it the wrong way round - you want 250K in the middle. It’s very easy to do this, just wire the switch as normal and connect the resistor from the bridge pickup terminal to ground.

(Actually you always want it like that, since the bridge pickup dominates in the middle position due to its lower impedance.)

Revolutions

ICBM said:

If you didn’t want the middle position bright you’ve got it the wrong way round - you want 250K in the middle. It’s very easy to do this, just wire the switch as normal and connect the resistor from the bridge pickup terminal to ground.

(Actually you always want it like that, since the bridge pickup dominates in the middle position due to its lower impedance.)

Thanks- don’t know why I didn’t try that after discovering that this doesn’t work for me. I’d read the middle position can be dominated by the neck pickup at 250k (& be too bright), so that’s why I sought out this other way. It’s a simple change so will give it a go & see how that sounds. 

strtdv

The other option would be to leave the tone control at 250k and wire the neck pickup to bypass the tone control entirely

Funkfingers

Revolutions said:

I ran into a small problem in the lugs on the Squier 3-way switch are different

Visualise the CRL selector switch contacts thus.

C 1 2 3
1 2 3 C

The Asian eight-in-line switch is 

1 2 3 C C 1 2 3

Simply translate your first schematic diagram to suit the budget switch.

BillDL

As Funkfingers mentioned.  Switches are split into two distinct sides that can be used independently.  To work for most purposes a wire is used to connect the "Common" lug (C) on one side to the common lug on the other side on wafer switches.  In the enclosed "import" switch the two (C) common lugs are adjacent to each other in the middle.  These are often already joined together, but if they aren't already joined it's pretty easy to bridge them with a wire.

Funkfingers

Revolutions said:

it’s lefty so everything is flipped.

Does that statement extend to the new 500k pots?

Connecting up right-handed audio/logarithmic resistance taper pots in a left-handed stylee is going to screw things up somewhat.