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"Take these three items, some WD-40, a vise grip, and a roll of duct tape. Any man worth his salt can fix almost any problem with this stuff alone." - Walt Kowalski
"Only two things are infinite - the universe, and human stupidity. And I'm not sure about the universe." - Albert Einstein
If you say "yes,you look lovely" they think your lying and if you say "no" they go off their tits.
Well let's take an average of the two lengths it must fall between... So that would be (zero + infinity) / 2 therefore the length of a piece of string is exactly half of infinity. Problem solved.
Don't know, but its length has a 30% chance of starting with a 1, regardless of what unit of length you use. And that really is true.
Supportact said: [my style is] probably more an accumulation of limitations and bad habits than a 'style'.
I'm not locked in here with you, you are locked in here with me.
lol
for those interested, check out Benford's law http://en.m.wikipedia.org/wiki/Benford's_law
Supportact said: [my style is] probably more an accumulation of limitations and bad habits than a 'style'.
They ask because you haven't already told them they look lovely.
Trick is to tell them this at the very first opportunity, ideally before they've even finished putting their make up on: "Really? But I haven't even finished getting ready yet! Oh thank you, darling...!"
Waiting for them to actually ask...that's a real noob mistake. The question isn't really "Do I look OK in this?" it is "WHY HAVEN'T YOU EVEN NOTICED WHAT I LOOK LIKE?! I GIVE YOU CHILDREN, I COOK YOUR FOOD, I WASH YOUR CLOTHES, AND FOR A BRIEF PERIOD AT THE BEGINNING OF OUR RELATIONSHIP I EVEN PERFORMED...YOU KNOW, THAT ACT ON YOU...AND NOW YOU HATE ME!"
For motorbike riding?
He'd look like the caped crusader (until the poncho gets caught on a truck...)
Oh, and WHY is it always BMW drivers that are blind to motorbikes?
2x Half it's length.
Similarly 0.3recurring IS 1/3. Just your calculator may well not use a way of doing the calculations that can handle the manipulation and instead multiplies up its finite (and imprecise) representation of it. Some symbolic maths packages do understand this kind of thing.